$6,000 is invested in each of two accounts, both paying 8% annual interest. In the first account, interest com?

This problem can be solved using a system of linear equations. Let x = the amount invested at 6% and let y = the amount invested at 7%. The expression to denote interest earned is expressed as: 0.06x + 0.07y = 467 In other words...some amount at 6% interest plus some amount at 7% interest will give us total interest earned for the year of $467.

The expression to show your investment is: x + y = 7,000 In other words...some amount plus some other amount will give us a grand total of $7,000. So when solving this system simultaneously... ...0.06x + 0.07y = 467 ...x + y = 7,000 We get x = 2,300 and y = 4,700. So $2,300 was invested at 6% and $4,700 was invested at 7%.

Hope this helps and good luck!