A sample of an ideal gas at 1.00 atm and a volume of 1.71 L was placed in a weighted balloon and dropped into?

Since you have an ideal gas, you know P1V1 = P2V2 1 * 1.63 = 45.0 * V2 therefore V2 = 1 * 1.63 / 45.0 ~ 3.62 * 10^-2 L or 36.2 mL.

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