A series ac circuit consists of a resistor R= 10 ohms, a capacitor C= 12microF and an inductor L = 12 mH.?

(a) Current will be maximum at resonant frequency (Fr). Fr = 1/{(2pi)*sq rt(LC)} = 1/{(6.28)*sq rt (.017)*(.000012)} = 352Hz (b) Xc = 1/(6.28)*(352)*(.000012) = 38 Ohms Xl = (6.28)*(352)*(.017) = 38 Ohms Z at resonance = 10 + j(38 - 38)Ohms = 10 Ohms I max = V/Z = 155V/10 Ohm = 15.5 Amps.

Resonance when Xc = Xl Xc = 1/2pifC Xl =2pi fL when Xc = Xl, then 1/2 pi fC = 2pi fL f^2 = 1/4 pi^2 LC f = 1 / (2 pi sqrt(LC)) = 17 * 10-3 * 12 * 10^-6) = .159 / sqrt(204 *10^-9) = .159 / sqrt(20.4 *10^-8) = .159 / (4.51 * 10^-4) = .0352 * 10^4 = 352 Hz LOL whatta coincidence a) 352 Hz b) I = V/R = 155/10 = 15.5 amps.

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