CH4 (g) + 2 O2 (g) yields CO2 (g) + 2 H2O The coefficients in a balanced equation determine the ratio of moles of reactants to moles of products. For this reaction, one mole of CH4 reacts with two moles of O2 to produce one mole of CO2 and two moles of water. The ratio for CH4 to H2O is 1:2.
This means the number of moles of CH4 is one half of the number of moles of H2O. At standard temperature and pressure, the volume of one mole of a gas is 22.4 liters. Let’s use the following equation to determine number of moles since the temperature and pressure are the same.
Number of moles = Volume ÷ 22.4 For H2O, n = 12.4 ÷ 22.4 For CH4, n = V ÷ 22.4 This is one half of the number of moles of H2O. V ÷ 22.4 = ½ * 12.4 ÷ 22.4 Multiply both sides by 22.4. V = 6.2 liters When the temperature and pressure are the same, the ratio of the volumes is equal to the ratio of the coefficients in a balanced equation. 1:2 = V/12.4 V = 6.2 liters I just wanted to prove that his true.
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