Si el mulo tomara un saco, su carga sería el doble que la del caballo m+1 = 2(c-1) si el mulo le da un saco al caballo, los dos tendrían la misma carga m-1 = c+1 despejamos m en las dos ecuaciones m+1 = 2(c-1) m+1 = 2c-2 m = 2c-2-1 m = 2c-3 m-1 = c+1 m = c+1+1 m = c+2 igualamos los valores de m 2c-3 = c+2 2c-c= 2+3 c = 5 >>>cantidad de sacos que lleva el caballo reemplazamos c m = c+2 m = 5+2 m = 7 >>>cantidad de sacos que lleva el mulo.
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