AlertDialog is not created even though I invoke onCreateDialog on Android?

Use onPrepareDialog() method to fill dialog with data. If you want dialog to be destroyed you should call removeDialog() method.

After I changed my code, the dialogs are being displayed with no contents. – rlc Sep 1 at 18:12 It depends on what you want to do. – Pixie Sep 1 at 18:15 You can call setText() for the TextView inside your dialog from onPrepareDialog() method.

– Pixie Sep 1 at 18:17 I want to use an inflater to set the layout of the alertdialog – rlc Sep 1 at 18:34 I am doing this and then changing the values... but it is not working... AlertDialog alertDialog = (AlertDialog) dialogIn; View dialoglayout = alertDialog. GetLayoutInflater(). Inflate( R.layout.

Dialog_user_info, (ViewGroup) findViewById(R.id. Dialog_user_layout_root)); AlertDialog. Builder builder = new AlertDialog.

Builder(this); builder. SetView(dialoglayout); – rlc Sep 1 at 18:35.

I believe that showDialog only calls onCreateDialog once, if the ID is the same. If you want to update an dialog which has already been created you can override onPrepareDialog to update whatever you like before it is shown to the user.

After I changed my code, the dialogs are being displayed with no contents. – rlc Sep 1 at 18:12.

And is ok because if you see the doc, the onCreateDialog is call in first time. "When a dialog is requested for the first time, Android calls onCreateDialog(int) from your Activity, which is where you should instantiate the Dialog. This callback method is passed the same ID that you passed to showDialog(int).

After you create the Dialog, return the object at the end of the method. " You need to know that this will be created once. Call onPrepareDialog."Before the dialog is displayed, Android also calls the optional callback method onPrepareDialog(int, Dialog).

Define this method if you want to change any properties of the dialog each time it is opened. This method is called every time a dialog is opened, whereas onCreateDialog(int) is only called the very first time a dialog is opened. If you don't define onPrepareDialog(), then the dialog will remain the same as it was the previous time it was opened.

This method is also passed the dialog's ID, along with the Dialog object you created in onCreateDialog().

D("PRINT 3", "onCreateDialog on switch.. `this. MyPhotoBar = (Gallery) findViewById(R.id.

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