An object moving at a constant speed travels the same distance every second?

1) Let the initital velocity be you ft/sec and the constant accelaration be a ft/sec² 2) The distance travelled in t seconds of time is given by: s = ut + (1/2)at² i) Distance travelled in 10 seconds time is: s(10): 10u + 50a ii) Distance travelled in 9 seconds time is: s(9): 9u + 40.5a Hence, distance travelled in 10th second is: s(10) - s(9): you + 9.5a = 24 ft ---- (1) iii) Similarly distance travelled in 12th second is: s(12) - s(11): you + 11.5a = 18 ft --- (2) 3) Solving the equations in (1) & (2) above, we get a = -3 ft/sec² and you = 52.5 ft/sec.

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