Area of a rectangle is 50 ft^2, and length of the rectangle is 5 ft less than three times the width. Find the dimensions of the rectangle.?

Let L and W represent the length and width of the rectangle, respectively. Area: LW = 35 Length: L = 3W – 8 Substitute 3W – 8 for L in Area equation: (3W – 8)W = 35 and solve equation 3W²? 8W – 35 = 0 (W?

5)(3W + 7) = 0 Now you can identify W, then you can compute L Can you take it from here so you can tell your instructor that YOU “completed” the exercise?

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