Bio Help Hardy-Weinberg Equation?

Let's say we have 100 individuals. Then we have 200 alleles total: 10 AA => 20 A alleles 20 Aa => 20 A + 20 a alleles 70 aa => 140 a alleles freq(A) = (20 + 20) / 200 = 0.2 (answer) freq(a) = (20 + 140) / 200 = 0.8 (answer) If A and a are the only alleles at the gene A locus, does the population seem to be a Hardy-Weinberg equilibrium? Let's say we have 100 individuals.

If in Hardy-Weinberg equilibrium we expect number of homozygote A individuals = freq(AA) * population size = (freq(A))^2 * population size = 0.2^2 * 100 = 4 number of heterozygote individuals = 2*freq(A)*freq(a) * population size = 32 number of homozygote a individuals = freq(a)^2 * population size = 64 Those numbers are nowhere near the 10. 20. And 70 that we observed.

This population is NOT in Hardy-Weinberg equilibrium. Something is stomping the heterozygotes.

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