Boost::asio::async_read bind compilation error?

Your completion handler signature is not correct, consider this example.

Your completion handler signature is not correct, consider this example #include #include #include void foo() { } int main() { boost::asio::io_service io_service; boost::asio::ip::tcp::socket socket( io_service ); char buf2; // this compiles file boost::asio::async_read( socket, boost::asio::buffer(buf), boost::asio::transfer_at_least(2), boost::bind( &foo ) ); // this does not boost::function cb = boost::bind( &foo ); boost::asio::async_read( socket, boost::asio::buffer(buf), boost::asio::transfer_at_least(2), cb ); } boost::bind is smart enough to not pass the error or bytes_transferred parameters to your bound function pointer. The author of the Asio library has a detailed blog post about using bind with the library. It is worth the read.

Thanks! And how is that, seems pretty much the same to me, doesn't it? – TheSquad Jun 28 at 22:08 one +1 for the answer, and if I could I would give you a second for the link to the blogpost, thank you, learned something again today ^^ – Thomas Berger Jun 28 at 23:16.

The async_* operations requires a different signature for the callback function: void handler( const boost::system::error_code& error, // Result of operation. Std::size_t bytes_transferred // Number of bytes read. ); Please have a deeper look at the documentation for some examples how to write and invoke such a callback handler.

1 This is the shared_ptr of the class : public shared_from_this, it is working well on other Classes, and this is not what the compiler is complaining about. Thanks – TheSquad Jun 28 at 21:50 sry, I was to fast again, but here you has you answer ;) – Thomas Berger Jun 28 at 21:58 Unfortunately I did, and this is why I don't understand... I am calling a simple void() function, and my callback is a boost::function... We really can't make it more simpler :-/ . – TheSquad Jun 28 at 22:01 no, you didn't, please have a look at this page.

There is the callback signature I posted you, NOT a void() function, it expects two paramters! – Thomas Berger Jun 28 at 22:09 those parameters are not obligatory... – TheSquad Jun 28 at 22:10.

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