Boyle's Law, Charles Law, or Combined Gas Law?

What is the value of the temperature of a gas that went from 355ml at 1.00atm and 64.0 c to 3.55l at 1.00 atm You need to pay more attention. This is really easy. You only need one formula and that is the combined gas Law.

If the problem gives you info for all three values P V and T then use combined gas law. If problem gives values for P and V then still use combined gas Law but IGNORE T. If the problem gives values for P and T but not V then use combined gas law but IGNORE V and same if it gives values for V and T but not P then ignore P.

So let's go back to your first question. What is the value of the temperature of a gas that went from 355ml at 1.00atm and 64.0 c to 3.55l at 1.00 atm P1 = 1.00 atm, V1 = 355 T1 = 64 + 273, V2 = 3.55, T2 = 1.00, and T2 is what you are looking for. Notice that in this case the P's are exactly the same?

So you can ignore them in the equation and just write V1 / T1 = V2 / T2 355 / 337 = 3.55 / T2 Cross multiply and divide to get T2 = 3.37 K which is -269.63 C.

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