Can someone help me solve this exponential equation? 25^2x=5^(1-x)?

Use parenthesis to indicate exponent...assuming it is: 4^(2x + 3) = 1 Note that 4^0 = 1..since anything raised to the power of 0 is 1...(maybe except 0)...so we have... 4^(2x + 3) = 4^0 Now since the bases are the same....the exponents must be the same as well so equate the exponents and solve for x...(i.e. A^b = a^c then be = c)...thus we have.. 2x + 3 = 0 Subtract 3 to both sides of the equation...to move that 3 to the other side and isolate the term with the variable.. 2x + 3 - 3 = 0 - 3 2x = -3 We want to get rid of that 2 in front of x by dividing both sides of the equation by 2 to isolate x...such that the division cancels out the multiplication... 2x/2 = -3/2.

Any number, when raised to the power of 0, will equal 1. Also, use brackets 4^(2x + 3) = 1 4^(2x + 3) = 4^0 2x + 3 = 0 Can you take it from there?

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