Can this polynomial be factored?

Yes is can! (x+1)(x+2)(x-3) Have a good day!

According to the Fundamental theorem of Algebra, f(x)=x^3-7x-6 has at least 1 real zero in the set of real numbers, call this zero a. By the factor theorem, (x-a) is a factor of f(x). Trial and error yields f(-1)=0, f(2)=0, and f(3)=0 f(x)=(x+1)(x-2)(x-3).

Yes. It helps to set the equation equal to zero in order to factor. X^3 - 7x - 6 =0 by inspection, we can see that x=-1 satisfies this equation.So factor out (x+1) (x+1)*(x^2-x-6) and x^2-x-6 also factors, giving you (x+1) * (x+2) * (x-3).

Yes. Its Factors are (x+2) , (x+1), and (x-3).

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