Check SQL database if value exists and then return value if it does?

$result I think will evaluate to true even if the result set contains zero rows. It only returns boolean false on error according to the manual. Use mysql_num_rows to determine if you actually found anything with the query if ($db_found) { $result =mysql_query("SELECT 1 FROM my_table WHERE Username = $username"); if ($result && mysql_num_rows($result) > 0) { echo 'Username and Password Found'; } else { echo 'Username and Password NOT Found'; } } else { print "Database NOT Found."; mysql_close($db_handle); }.

$result I think will evaluate to true even if the result set contains zero rows. It only returns boolean false on error according to the manual. Use mysql_num_rows to determine if you actually found anything with the query.

If ($db_found) { $result =mysql_query("SELECT 1 FROM my_table WHERE Username = $username"); if ($result && mysql_num_rows($result) > 0) { echo 'Username and Password Found'; } else { echo 'Username and Password NOT Found'; } } else { print "Database NOT Found. "; mysql_close($db_handle); }.

Try this for your SQL: $result = mysql_query("SELECT 1 FROM my_table WHERE Username = " . Mysql_escape_string($username)); Note: You are using mysql interface, which according to PHP has been deprecated as of 5.3.0, so your code will not have much of a shelf-life, consider using PDO.

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