Color blindness is X-linked recessive A man with color blindness marries a normal woman with no history of the disease in her family She is not a carrier What is the chance of their kids having it?

Using the Punnet square, if the male is xY and the female is XX, where x = recessive and X = dominant, then males get the disease since they only have 1 x chromosome. Females can be carriers, Xx, or have the disease..xx, or not at all XX so X X (female none carrier) x Xx Xx Y XY XY (male carrier) Leaves you with 100 percent chance of daughters being carriers, and 100 Percent chance for sons being healthy none carriers.

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