Compare two generic Lists?

Assuming ICollection x and List y If order of the records matters: return x. SequenceEqual(y) If order doesn't matter, I think your best option is to skip LINQ and use a HashSet.

Assuming ICollection x and List y... If order of the records matters: return x. SequenceEqual(y); If order doesn't matter, I think your best option is to skip LINQ and use a HashSet: return new HashSet(x). SetEquals(y).

Caveat though: ICollection x = new List {1}; List y = new List { 1, 1, 1 }; bool areEqual = new HashSet(y). SetEquals(x); //true That may be what you want, but if you want to know if the items in the lists are the same and the items are in the list the same amount of times, this won't work. Kudos though for learning me about SetEquals.

I've never noticed it :) – aquinas Jun 24 at 3:24 A good point (note that an Intersect()-based solution suffers the same fate). If duplicates must be preserved, I'd either sort each list and use SequenceEquals() or group by element and use SetEquals() on item/count pairs. – dahlbyk Jun 24 at 3:31.

Here is a sample code depending on whether sequence is important or not : ICollection collection1 = new List { 5, 1, 6, 7, 3 }; List collection2 = new List { 1, 5, 6, 7, 3 }; bool considerSequence = true; // sequence is important bool areEquael; if (considerSequence) { areEquael = collection1. SequenceEqual(collection2); } else { areEquael = collection1. OrderBy(val => val).

SequenceEqual( collection2. OrderBy(val => val)); } As suggested by other colleagues also consider using HashSet. Just take into account that HashSet is available only starting from .

NET Framework 3.5.

List lst = new List(); List lst1 = new List(); bool result = false; if (lst. Count == lst1. Count) { for (int I = 0; I lst = new List(); lst.

Add(1); lst. Add(51); lst. Add(65); lst.

Add(786); lst. Add(456); List lst1 = new List(); lst1. Add(786); lst1.

Add(1); lst1. Add(456); lst1. Add(65); lst1.

Add(51); bool result = false; if (lst. Count == lst1. Count) { result = lst.

Union(lst1).Count() == lst. Count; } if (result) { Response. Write("list are same"); } else { Response.

Write("list are not same"); } try this one also.....

This assumes that the order of the lists is exactly the same, not just the items in the list. I think the original question was just about set identity. – aquinas Jun 24 at 3:18.

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