Convert UTF-8 octets to unicode code points?

I'm assuming pre-3.x... Put them in a str, and either call unicode with the string and 'utf-8': >>> unicode('\xc5\x81', 'utf-8') u'\u0141' Or call . Decode('utf-8') on the str: >>> '\xc5\x81'. Decode('utf-8') u'\u0141' If by "octet" you really mean a string in the form '0xc5' (rather than '\xc5') you can convert them like this: >>> ''.

Join(chr(int(x,0)) for x in '0xc5', '0x81') '\xc5\x81.

1, well explained! – YOU Dec 8 '09 at 5:11 1 +1: Also, int(x,0) has the advantage of permitting mixed base octect string, for example, '0xc5', '0x81', '0305', '0201' are the hex and octal representations of the same. Int(x,16) would misinterpret the octal strings in this input – mhawke Dec 8 '09 at 5:42.

L = '0xc5','0x81' s = ''. Join(chr(int(c, 16)) for c in l). Decode('utf8') s >>> u'\u0141.

In lovely 3. X, where all strs are Unicode, and bytes are what strs used to be: >>> s = str(bytes(0xc5, 0x81), 'utf-8') >>> s 'ŝ' >>> ord(s) 321 >>> hex(ord(s)) '0x141' Which is what you asked for.

. Join((chr(int(x,16)) for x in '0xc5','0x81')). Decode("utf8") u'\u0141.

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