Dados os conjuntos A={1,2,3,4}, B={3,4,5,6,7} e U={0,1,2,3,4,5,6,7,8,9},em...?

Resolução: Os recíprocos são: 1/10; 1/5; 1/3; 1/4; 1/5; 1/10; 1/3; 1/8; 1/9; 1/3. Fazendo a média desses valores, temos: (1/10) x (1/10)+(1/5)+(1/3)+(1/4)+(1/5)+(1/10)+(... Agrupando os termos iguais: (1/10) x (1/4)+(1/8)+(1/9)+{3.(1/3)}+{2.(1/5)}+{... Simplificando ‘2’ com ‘10’: (1/10) x (1/4)+(1/8)+(1/9)+{3.(1/3)}+{2.(1/5)+(1... Agrupando ‘2/5’ com ‘1/5’; agrupando ‘1/4’ com ‘1/8’: (1/10) x (2/8)+(1/8)+(1/9)+{3.(1/3)}+{3.(1/5)} Fazendo as divisões: (1/10) x (0,375)+(1/9)+(1)+(0,6) Observe que 1/9 é uma fração mais “complicada”. Dá uma dízima periódica. Vamos.

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