Decrypting RSA data in .NET with only a few values?

There are two representations for an RSA private key (cf PKCS#1 ).

There are two representations for an RSA private key (cf PKCS#1). The first representation consists of the pair (n, d), the second representation consists of a quintuple (p, q, dP, dQ, qInv). The public key is represented as (n, e).

N is the public modulus p and q are the two primes d is the private exponent e is the public exponent dP is p's Chinese Remainder Theorem coefficient ( e · dP ≡ 1 (mod (p – 1)) ) dQ is q's CRT coefficient ( e · dQ ≡ 1 (mod (q – 1)) ) qInv is a CRT coefficient, a positive integer less than p such that q · qInv ≡ 1 (mod p) Each of the two private key representation is "complete", i.e. You only need one of them to be able to perform RSA computations. Since you are in possession of everything that is necessary for the first representation, it suffices to only set these parameters (i.e.

N, p, q, e, d) on your RSAParameters instance and omit the rest.

The Javascript key generator creates an array of 28 bit integers. Is it correct to extend them to 32 bits and represent them as little endian when converting them to a byte array? – Charlie Somerville Jul 21 at 13:16 To be on the safe side, I'd use BigInteger#Parse(String)?

– emboss Jul 21 at 23:17.

This Wikipedia page seems to contain instructions on how to calculate these parameters, namely The values dp, dq and qInv, which are part of the private key are computed as follows: dp = d mod (p − 1) dq = d mod (q − 1) qInv = q^−1 mod p.

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.