In your second snippet, you should be able to refer to your DataContext as a DynamicResource.
In your second snippet, you should be able to refer to your DataContext as a DynamicResource: DataContext="{DynamicResource WidgetViewModel}" But most custom user controls have some sort of top level layout container, and you can set the DataContext on that container as a StaticResource. In your case, however, you may want to consider dropping the VM portion of your code altogether since you're writing a custom UserControl. You should ask yourself what benefits are you gaining from a completely self-contained ViewModel with no real backing Model designed for just one View (i.e.
The custom UserControl). Perhaps you could just define some DependencyProperties and use those?
Thank you, this worked well (although I'd rather prefer a solution that wouldn't change program at all at runtime). – TomáÅ¡ Kafka Jun 16 '09 at 22:24.
I came up with several solutions: Add DC as resource (it will get automatically instantiated with parameterless constructor), and do the following in View's codebehind: public PanelView() { InitializeComponent(); if (!DesignerProperties. GetIsInDesignMode(new DependencyObject())) //DeleteAtRelease: { //we are in runtime, reset DC to have it inherited this. DataContextHolder.
DataContext = DependencyProperty. UnsetValue; } } Better way would be to only assign DC if we are at designtime, but VS didn't like it - it worked only sometimes, and quite nondeterministically, and once it even crashed. Other check for design time is: if (LicenseManager.
UsageMode == LicenseUsageMode. Designtime) { this. DataContext = new WidgetViewModel(); }.
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