Do I need to overload methods accepting const lvalue reference for rvalue references explicitly?

Write one function. Take it in by value, then move it void Person::set_name(std::string name) { this->name_ = std::move(name); } Let the std::string decide how to copy itself.

Write one function. Take it in by value, then move it. Void Person::set_name(std::string name) { this->name_ = std::move(name); } Let the std::string decide how to copy itself.

1 Unfortunately, you need to be sure that the parameter type supports move, otherwise you'll end up with two copies. Is there a way to do this generically and without turning the function into a template? – avakar Sep 28 at 17:32 As long as the parameter supports move semantics this solution works perfectly.In the worst case (passing lvalue references) it will introduce only minimal overhead (one additional move assignment, so really cheap).

I like it. Thanks – Stefan Haller Sep 29 at 11:55.

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