Dos buenas noticias!?

Hola H : altura común a las torres x1 : Distancia horizontal del observador a la primera torre tan(43º) = H/x1 x1 = H/tan(43º) tan(38º) = H/x2 x2 = H/tan(28º) Suma de distancias horizontales x1 + x2 = H ( (1/tan(43º)) + (1/tan(28º)) ) = 200 m H = (200 m) / ( (1/tan(43º)) + (1/tan(28º)) ) H = 67.7 m Como verificación el punto de observación está separado horizontalmente.

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.