¿Dos coches circulan a velocidades respectivas de 36 km / h y 108 km / h por una autopista. Si inicialmente l?

La distancia recorrida por los coches más la distancia que los separa después de 3 horas forman un triángulo. Para calcular tal distancia se resuelve usando el teorema del coseno, pero antes se calculan los lados conocidos: be = 40 * 3 = 120 Km c = 70 * 3 = 210 Km La fórmula es: a^2 = b^2 + c^2 - 2bc * cos A Por tanto: a^2 = 120^2 + 210^2 - 2 * 120 * 210 * cos 29º a^2 = 14.400 + 44.100 - 50.400 * 0,8746 a^2 = 58.500 - 44.079,84 a^2 = 14.420,16 a = 120,08 Km (redondeado) Después de 3 horas, los coches están separados por 120,08 Km.

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.