Dynamically find out how many inputs a function has, Racket?

You can use procedure-arity. (procedure-arity expt) ; => 2 Note that when using procedure-arity with variadic functions or case-lambda or the like, the results are more complicated: (procedure-arity apply) ; => (arity-at-least 2) (procedure-arity (case-lambda ((x) x) ((x y z) z) ((a be c d e f . G) g))) ; => `(1 3 ,(arity-at-least 6)).

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