Electron configuration for silver ion?

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 4d10 that's for silver simplified to Kr 5s1 4d10 The down electron from the 5s moves to fill the d orbitals because it is more stable there a+1 ion (silver's only oxidation state) would be Kr 4d10 Outer orbitals are always removed first, so you cannot start to remove the 4d electrons until all of the 5s are gone.

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