Equivalent to (.*) in negative look behind assertion Regex Python?

Problem: Lookbehind does not allow pattern whose length is not fixed.

Problem: Lookbehind does not allow pattern whose length is not fixed. Quick hack: Perhaps the following regexp does the job? R'(?>> str = """test.com/aa4 ... bx2 vq9 ... bh9.com/cj3 ... """ >>> re.

Findall(r'(?

How does . / perform the functionality? – thinkcool Jul 15 at 8:12 @thinkcool: .

/ matches a dot or a slash. I.e. The regexp presented in my answer matches all words a-za-z0-9 which do not follow a dot or a slash.

– phynfo Jul 15 at 8:45 what happens when the pattern just follows a . Or . / It will not match .

Fd3 . Is there any foolproof solution? – thinkcool Jul 15 at 13:22 I am not able to understand your newly edited answer.

Can you tell me how to proceed with this? – thinkcool Jul 150 at 21:42.

That not possible. Python allows only fixed length lookbehinds. That means no quantifier inside the lookbehind.

See here the feature list on egular-expressions.info.

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