Evaluating limits using a table?

Use a substitution. If you let kx = 1/n x = 1/(nk) then lim {as x app 0+} kx = lim {as n app inf} 1/n = 0 Substituting, we have lim {as x app 0+} (1 + kx)^(5/x) = lim {as n app inf} (1 + 1/n)^(5nk) lim {as n app inf} (1 + 1/n)^(n)^(5k) e^(5k) Hope this helps!

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