Exercícios de matemática, me ajudem!?

Boa tarde Se são perpendiculares entre si, então seus coeficientes angulares têm sinais contrários. X + 2y = 3 2y = -x + 3 y = -x/2 + 3/2 y = ax + be y = (-1/2)x + 3/2? Coeficiente "a" = -1/2.

Ax + 3y = -2 3y = -ax - 2 y = -ax/3 - 2/3 y = ax + be y = (-a/3)x - 2/3? Coeficiente "a" = -a/3 Logo, devemos ter: -1/2 = -(-a/3) -1/2 = a/3 a = 3*(-1/2) a = -3/2.

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