SELECT * FROM authorizations a WHERE NOT EXISTS ( SELECT NULL FROM Settlements s WHERE s. Auth_id = a. Id AND s.
Status = 'ACCEPTED' ).
1 beat me to it by a hair – Eric Petroelje Aug 10 '09 at 17:30 Thanks! This worked perfectly. – MikeQ Aug 10 '09 at 18:39.
Based on your example, checking for the s. Status being null is unnecessary if you change the JOIN to be a RIGHT join. Will work with SQL Server 2005+ or Oracle 9i+: WITH unacceptedSettlements AS ( SELECT s.
Auth_id FROM SETTLEMENTS s WHERE s. Status! = 'ACCEPTED' GROUP BY s.
Auth_id) SELECT t. * FROM AUTHORIZATIONS t JOIN unacceptedSettlements us ON us. Auth_id = t.
Auth_id Any database alternative: SELECT t. * FROM AUTHORIZATIONS t JOIN (SELECT s. Auth_id FROM SETTLEMENTS s WHERE s.
Status! = 'ACCEPTED' GROUP BY s. Auth_id) us ON us.
Auth_id = t. Auth_id.
Both your solutions will not return an authorization if there is no corresponding record in settlements. In the @op's example, authorization 2 will not be returned. – Quassnoi Aug 10 '09 at 17:56 Per the OP: "How can I only fetch single authorization records that don't have a corresponding settlement record with a status of "ACCEPTED"?"
There's no requirement stated for needing AUTHORIZATION records without any SETTLEMENT records. – OMG Ponies Aug 10 '09 at 18:09 Authorization 2 doesn't have a corresponding settlement record with a status of ACCEPTED. That was the whole point of the LEFT JOIN in the original query.
– Quassnoi Aug 10 '09 at 18:21 Then why does the supplied query contain "status! = 'ACCEPTED'"? – OMG Ponies Aug 10 '09 at 18:24 Because the @op made it wrong.
– Quassnoi Aug 10 '09 at 18:29.
Try SELECT a. * FROM authorizations a LEFT OUTER JOIN (SELECT S. * from settlements s1 WHERE s1.
Status = 'ACCEPTED') ON a. Id = s. Auth_id WHERE s.
Auth_id is null This picks out all the records which are accepted and then takes the authorizations which are not inthat group.
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