Finding the intersection of a plane using reduced row echelon form?

Well, ok, but its the long way around. V4 = -4v1, so we know right off the bat they are linearly dependent. I'll write them as column vectors, although you could write them as row-vectors, either method would work.

1 .0 0 -4 0 .2 0 .0 -1 .0 0 .4 0 -2 3 .0 add row 1 to row 3: 1 .0 0 -4 0 .2 0 .0 0 .0 0 .0 0 -2 3 .0 swap rows 3 and 4: 1 .0 0 -4 0 .2 0 .0 0 -2 3 .0 0 .0 0 .0 add row 2 to row 3.

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