Function within function in PHP?
It works, but the scope of test2() is limited. For example, this works: wally@zf ~$ cat y. Php wally@zf ~$ php -f y.
Php 123wally@zf ~$.
Wallyk thank you for the insight, this indeed works now. Can you explain why you require x to be redeclared once again as a global in the second function? – chicane Dec 4 '09 at 1:45 It's so that $x can be seen outside the respective functions.
If $x=123 were set outside test1(), there would be no need for test1() to have global $x. – wallyk Dec 4 '09 at 1:53.
I'm having trouble picturing a use-case for this.
You're not calling the function test2 so there's no reason for it to echo $x. Besides, you should construct the function outside, there's no added value in this case.
Return ($value); //stops execution of the function and returns its argument as the value at the point where the function was called. One may have more than one return()statements in a function. Print("This Line is not Bold.
Print("This Line is not Italics.
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