Generate list of of files (with revision) which belongs to a specific cvs-tag?

The most simple solution is to do a checkout with this tag somewhere. Takes a bit of disk space, though. If that bothers you, try what you get with the p option.

If this output contains file names, then you just need to filter them out.

The most simple solution is to do a checkout with this tag somewhere. Takes a bit of disk space, though. If that bothers you, try what you get with the -p option.

If this output contains file names, then you just need to filter them out.

The list will be a little more verbose than what you want but you could simply do: cvs log -S -N -r projectname_a or possibly (if you don't have the project checked out): cvs rlog -S -N -r projectname_a ModuleName (you can use ". " (w/o quotes) as the module name if you want to scan the entire repository) If you only want the file names without the revision information, add -R.

No need to check anything out - you can use the rls command (remote list). It will give you information in a slightly funny way but it is straightforward to process. Cvs rls -r -eR Here's my script snippet: for NAME in `cvs rls ${MODULE} -r ${TAG} -eR | grep -v ^$ | grep -v ^D | sed 's/ /~~/g'` do FIRST_CHARACTER=`echo $NAME | cut -c1,1` if ${FIRST_CHARACTER} = "/" then # This is a file FILE_NAME=`echo $NAME | awk -F/ '{print $2}'` VERSION=`echo $NAME | awk -F/ '{print $3}'` echo "${DIR_NAME}/${FILE_NAME},*${VERSION}*" else # This is a dir DIR_NAME=`echo $NAME | awk -F: '{print $1}'` fi done.

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