Get Python function's owning class from decorator?

If fn is an instancemethod then you can use fn. Im_class class Foo(object): ... def bar(self): ... pass ... >>> Foo.bar. Im_class __main__.

Foo Note that this will not work from a decorator, because a function is only transformed into an instance method after the class is defined (ie, if specialTest was used to decorate bar it would not work; if it's even possible, doing it at that point would have to be done by inspecting the call stack or something equally unhappy).

If fn is an instancemethod, then you can use fn. Im_class. >>> class Foo(object): ... def bar(self): ... pass ... >>> Foo.bar.

Im_class __main__. Foo Note that this will not work from a decorator, because a function is only transformed into an instance method after the class is defined (ie, if @specialTest was used to decorate bar, it would not work; if it's even possible, doing it at that point would have to be done by inspecting the call stack or something equally unhappy).

That's what I was afraid of. Thanks. – Corey Coogan Oct 7 at 12:24 For some reason this didn't register until I went back into the code.

This is possible, I simply have to move my code that interacts with the FN inside the wrapped function, where FN is an instance. – Corey Coogan Oct 7 at 14:25.

In Python 2 you can use im_class attribute on the method object. In Python 3, it'll be __self__. __class__ (or type(method.

__self__)).

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