Help solving a differential equation - thank you!?

After you find the IF, etc... you can check your answer: (find c1 with initial conditions) y(x) = c_1/(x+4)^6+1/10 (x+4)^4.

My diff eq is rusty, but I'm bored, so here's what I got. Y'=dy/dx=(x+4)^3-6y/(x+4) dy=((x+4)^3-6y/(x+4))dx? Dy=?(x+4)^3dx-?6y/(x+4)dx y=(1/4)(x+4)^4-6y*ln(x+4)+C y(1+6*ln(x+4))=(1/4)(x+4)^4 +C y=(1/4)(x+4)^4 +C/(1+6*ln(x+4)) 3=(1/4)(0+4)^4 +C/(1+6*ln(0+4)) 3=4^3 +C/(1+6*ln4) C=3+18*ln4-4^3 y=(1/4)(x+4)^4 +3+18*ln4-4^3/(1+6*ln(x+4)).

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