Hey help? math 10pts asap?

Before you do the question Remember that for 2 lines to be perpendicular, the product of their gradient must be -1 (m1*m2=-1) and the point-gradient formula; y-y1=m(x-x1). Since the equation of the given line is in the form y=mx+b, the gradient of that line is -4. Now since the line you wanted to find out is perpendicular to this, its gradient must be 1/4 (-4*1/4=-1).

Now you found the gradient of your line, you the point-gradient formula to find the equation of your line; substitute -12 into x1 and 0 into y1 and rearrange; y-0=1/4(x+12) y=x/4+3 or if you want to convert it into the general form; 4y=x+12 x-4y+12=0.

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