How can I return all the columns of a table using multiple distinct columns in Linq?

You want to use GroupBy: var distinctModelYears = cars. GroupBy(c => new { c. Year, c.

Model }) . Select(g => g.First()) //Take one from each group That will find all "distinct" years and models so there will only be one 2008 Accord, one 2009 Accord, etc.

You want to use GroupBy: var distinctModelYears = cars. GroupBy(c => new { c. Year, c.

Model }) . Select(g => g.First()) //Take one from each group ; That will find all "distinct" years and models so there will only be one 2008 Accord, one 2009 Accord, etc.

Taking the above example, say I have columns like Year, Model and Make. I need to return all the columns (Year, Model and Make) Group by Year and Model. So, combination of Year and Model will be unique.

– Mohit Dec 11 '09 at 21:18.

Var query = from TableA in ds. Join TableB in ds. Tables1.AsEnumerable() on new { col1 = TableA.

Field("colA"), col2 = TableA. Equals new { col1 = TableB. Field("colA"), col2 = TableB.

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