How do I solve this differential equation: m(dv/dt)=mg-kv^2?

M(dv/dt)=mg-kv a(t) = g - (k/m)v(t) So the answer is: a'(t) + (k/m)a(t) = 0 Which yields the solution: a(t) = a(0)e^(-k/m)t.

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