How do you find the median of a string of thousands of numbers in an Excel spreadsheet?

I didn't know if there is some formula you can enter for this or if there is an Excel function somewhere that will do this at the click of a button. Asked by ~Smiley~ 49 months ago Similar questions: find median string thousands numbers Excel spreadsheet Computers > Software Development.

Similar questions: find median string thousands numbers Excel spreadsheet.

There is a Median function in Excel. All you should have to do is group the list of numbers in the median function. Order is not important.

Median will order the numbers and pick the number in the center of an odd number of values, or average the 2 center values in an even number of values. There is no "middle number" in an even number of numbers. Median will average the 2 numbers it finds in the middle after ordering them.

The format for the formula is: =Median(A1..A3000) You say that you have a string of thousands of number. Each number needs to be in an individual cell. If this is not the case, all is not lost yet.

If the numbers are separated by commas in a text field, just rename the file with a . Csv ending, and open the new file in Excel. Each number should be in its own cell, and your formula will look like: =Median(A1..ZZ1) If they are not separated by comma's, you can open the file in MS Word, and replace the separator with a Paragraph Mark.

That will put each number on its own line. Save this file as a . Csv file and open it in Excel.

I hope this helps.

MEDIAN(A1:A1000) It's as simple as that. The MEDIAN() function will return the median of a range of numbers. Keep in mind the definition of Median: For an odd number of numbers, the median is the 'middle' one if they're in sorted order.

For example, if you have nine numbers, and you sort them, the median is the fifth one (there are four less than it and four higher than it). For an even number of numbers, the median is the arithmetic mean (ie, average) of the two "middle" numbers. For example, if you have 10 numbers, the median is the average of the fifth and sixth (there are four less than the fifth, and four greater than the sixth).

If you want the average instead, use the AVERAGE() function. Sources: Excel .

Use the "median" function Preface: When I look at this in its final form before I submit it, the spacing isn't correct with the column and row numbers at the top of my numbers. There are nine of them, and there are nine numbers, so you may have to imagine them in the correct place. I tried to fix it, but Askville does not have a great word processing function.(Or I just haven't read the manual.

) Use the function "median". Below are the first 9 numbers in your series of thousands (I hope you are talking about numbers that are in separate cells, and not one very big string of numbers in one cell.) Below is a series of random numbers, with the cells they are in. To find the median, use this formula: =median(A1:I1) You should get this answer in the cell with the formula: 0.569800 Of course, you can do this with as many cells as you have numbers in.

If you have numbers in more than one row, say they are also in Row 2, then do this: =median(A1:I1,A2:I2) separate each group with commas. A1 B1 C1 D1 E1 F1 G1 H1 I1 0.816352 |0.5698 |0.999857| 0.504787| 0.033233 |0.15074 |0.046333 |0.898872 |0.590781 I hope I haven’t confused you further. If this has sparked other questions, send me a PM.

I’ll try to get back to you as quickly as possible. Sources: This is one of the things I do .

Use the MEDIAN() function Say, your numbers are located in cells A2:A6498, so to find the median, you can do: =MEDIAN(A2:A6498) .

Sort by increasing or decreasing size on that column. Then, if the number ("N") of entries in that column is odd, ..... calculate M=(N+1)/2, and the entry at row M will be the median (if the rows with entries go from 1 to N). If N is even, calculate M=N/2, and the median will be somewhere between the entry at row M and the entry at row M+1, inclusive (if the rows with entries go from 1 to N); exactly *where* it falls between (and including) those two entries depends on the real-world conditions of the problem that you are trying to solve (unless, of course, you are lucky enough for the two entries to be equal).

If there is an Excel function that returns the median, some choice for where between the two middle entries the median falls will be hard-coded into it and will frequently give the wrong answer -- for instance, if "halfway between" is what it assumes, then, when the two middle values are different, it will return a number that is not even in the column and therefore probably makes very little sense.

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I am looking for a scanner and software that will scan isbn on books and read them into an excel spreadsheet.

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