The vector tangential to your original line has the components.
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Through 2 given points runs a line (K1 and K3). I want to compute (find) 2 others points (X1,X2), which are parallel to given points. Also I have center point(K2) between first and last point on this line.
Illustration I have K1,K2 and K3 How to find X1 and X2? I'm coding in C# in WPF, and I don't know how to solve this problem... please, help me Roberto math computational-geometry link|improve this question asked May 7 '11 at 11:25Roberto82.
The vector tangential to your original line has the components t_1 = K3_1 - K1_1 t_2 = K3_2 - K1_2 A normal vector to this line would be n_1 = t_2 n_2 = -t_1 The length of the vector n is equal to the distance from K1 to K2. Since you actually want a quarter of this distance, your final result is X1_1 = K1_1 + 0.25 * n_1 X1_2 = K1_2 + 0.25 * n_2 X2_1 = K2_1 + 0.25 * n_1 X2_2 = K2_2 + 0.25 * n_2 Note that you could choose the opposite sign for n, in which case you'd end up with a parallel line translated by the same distance in the opposite direction.
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