Include #include ... rc = fprintf(...) if (rc.
1 You should not declare errno yourself, just include ; it might be a macro, not a variable. – Mike Seymour Apr 20 at 7:52 point taken. Libc os dependent.
I think on older linux libcs you'd have to declare it extern tho. Corrected. – sysfault Apr 20 at 8:01 Err, adirau, that's even worse.
#ifndef will only work for preprocessor macros, not variables. You're better off ditching that whole #ifdef block since ISO mandates that errno. H defines an errno "variable".
I fixed it up for you, hope you don't mind. – paxdiablo Apr 20 at 8:19 but errno is a preprocessor macro, at least on unix and linux :) – sysfault Apr 20 at 10:46 I used the ifdefs thinking of the old errno libc linux implemenation where errno is(/was? ) exactly an int; so if errno isn't a cpp macro then it should be declared extern but those are oldtimes you are right – sysfault Apr 20 at 10:53.
You need to check the value of errno. Most library functions will set it to the specific error code and you can either look it up in errno. H or use perror or strerror to get a user-readable version.
For example: #include #include #include int main (void) { FILE *fh = fopen ("junk", "w"); if (fh! = NULL) { if (fprintf (fh, "%s", "hello").
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