If you want to do comparisons with second-largest or third largest/smallest then can use RankedMax.
Eqs = {x1, 3 x1 - x2, x2 - x1}; ReduceMaxeqs >= 2 Mineqs, {x1, x2}, Reals If you want to do comparisons with second-largest or third largest/smallest then can use RankedMax As far as solving it for x2 -- there are many different values of x2 corresponding to each x1 so you can't solve it in the conventional sense, you can see it from RegionPlot RegionPlotMaxeqs >= 2 Mineqs, {x1, 0, 1}, {x2, 0, 1}, PlotPoints -> 100.
Yaroslav Bulatov: in version 2||(c2||(a2". You may get quite a large number of equations this way, don't know an efficient way to do it, sorry – Yaroslav Bulatov Jan 14 at 0:47 @Yaroslav Bulatov: is there any way in Mma 7.0 to write one's own function which is equivalent to RankedMax in Mma 8.0? – Qiang Li Jan 14 at 3:11.
Use Max and Min and specify x2 before x1 in the variable list, as follows In1:= Reduce Maxx1, 3 x1 - x2, x2 - x1 >= 2 Minx1, 3 x1 - x2, x2 - x1 && 0.
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