How to sort on the Value of an member of a List within a parent List?

Well List x. Value) but even Sort isn't too bad: lmo. Sort((x, y) => x.Value.

CompareTo(y. Value)) EDIT: Having read the comment to the question, I no longer understand the question! Leaving this answer here as a potentially useful placeholder while I have dinner.

Well, List already has a Sort method if you want to sort it in place - or you could use LINQ's OrderBy method. OrderBy is slightly easier than Sort: var sorted = lmo. OrderBy(x => x.

Value); but even Sort isn't too bad: lmo. Sort((x, y) => x.Value. CompareTo(y.

Value)); EDIT: Having read the comment to the question, I no longer understand the question! Leaving this answer here as a potentially useful placeholder while I have dinner...

Int MyObjectComparison(MyObject x, MyObject y) { return x. Setting0.Value. CompareTo(y.

Setting0. Value); } lmo. Sort(MyObjectComparison); Of course, this assumes that you want to use the Value of the first element in setting (and that setting is guarunteed to have at least one element).

Solution with less assumption will be forthcoming when more info is given.

Since you are using 3.0, use LINQ: var newList = lmo. OrderBy(i => i. Value); and var newList = lmo.

OrderByDescending(i => i. Value).

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