I need help on this Algebra question please! Thanks!?

Initial kinetic energy = ½mv² = ½ * 45 kg * (5 m/s)² = 562.5 joules The box is brought to rest, so its final kinetic energy = 0 joules {using work energy theorem} work done by friction = change in kinetic energy = 562.5 J work done = friction force * distance moved against that force {re-arranging} friction force = work done / distance = (562.5 J / 3 m) = 187.5 newtons Floor is horizontal, so normal force = weight force = (mg) = (45 kg * 10 m/s²) = 450 newtons coefficient of friction = friction force / normal force = (187.5 N / 450 N) = 0.42.

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.