In how many ways can you arrange the digits 8,7,6 and 3 to form a four-digit number divisible by 9, using each?

To be divisible by 6, a number must be divisible by both 2 and 3 521 is not divisible by 2 because it is odd 521 is not divisible by 3 because sum of digits is not divisible by 3 521 is not divisible by 6 NOTE: We really only needed to show that 521 was not divisible by 2 OR 3 (we didn't need to show both).

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.