No. What you're describing is more akin to duck typing.
No. What you're describing is more akin to duck typing. Does a subclass of class A which implements interface I inherits the conformance to that interface, or should it also declare itself as implementing I?
Assuming you mean: public class A implements I { /* ... */ } public class B extends A { /* ... */ } In this case, B implements I.
", the answer is "no". Class B conforms to its parent and need not redeclare the interface. The best way to answer questions like these is to experiment - try it and see.
" point -- something well worth conveying more regularly. – delfuego Dec 24 '09 at 19:51.
No, interfaces must be explicitly implemented. Interfaces implemented by base classes are by extension always implemented by derived classes.
As a corollary, an abstract class that implements an interface may defer the implementation to a concrete subclass: java.sun.com/docs/books/tutorial/java/Ia... – trashgod Dec 24 '09 at 21:48.
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