Is there any difference between initializing a byte with ASCII and Hex form in Java?

Yes, they are absolutely the same. Both get converted to an int with the same value.

That depends on the value of -encoding to javac. If you pick a sufficiently 'interesting' encoding, 'C' won't be 0x42.

– Nayuki Minase yesterday Yes indeed I am. – bmargulies 23 hours ago But I have used this method to form a packet and sent to the device, it responded with response packet, so does it mean the encoding is correct? – Ghost_000_cs 22 hours ago Don't see the relevance of this answer as his code as-is will not compile with javac -encoding Cp1047 – Perception 22 hours ago 2 Is this right?

According to JLS (3.1, 3.10.4), internally all strings/characters in Java use UTF-16 encoding. The -encoding option to javac only controls the encoding of the source file.In your example, 'C' has already been decoded from the source file (because we are viewing it), so when the char is cast to an int it will be converted with UTF-16 charset, not the charset of the source file. – prunge 20 hours ago.

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