Java parse float without creating a float number with exponential?

Use this instead new java.lang. BigDecimal(value_.toString()) BigDecimal's are really decimal numbers and not floating point numbers. The scale of 2 (2 decimal digits) will remain.

Use this instead new java.lang. BigDecimal(value_.toString()); BigDecimal's are really decimal numbers and not floating point numbers. The scale of 2 (2 decimal digits) will remain.

The default output format of float is scientific notation above a certain size. If you want to output it in normal decimal notation, use NumberFormat with a format string of "#.00" whenever you print it.

Float is 32-bit bit and has up to 7 digits or accuracy. If you want more accuracy, use double which is 64-bit and has up to 16 digits of accuracy (in fact, always use double or BigDecimal) String text = "13299802.60"; System.out. Printf("As float %.2f%n", Float.

ParseFloat(text)); System.out. Printf("As double %.2f%n", Double. ParseDouble(text)); System.out.

Println("As BigDecimal "+ new BigDecimal(text)); prints As float 13299803.00 As double 13299802.60 As BigDecimal 13299802.60.

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.

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