Var x = new Array; $('. MyID'). Each(function(index) { xindex = $(this).position().
Left; }); console. Log(x) try that and see what is present in the array x.
Var x = new Array; $('. MyID'). Each(function(index) { xindex = $(this).position().
Left; }); console. Log(x); try that and see what is present in the array x.
You should not use id on more than one element. The appropriate attribute to use is class. Bla bla And then your code should work if you update the selector to be: $('.
MyClass').
. MyID is still a class #myID would have caused problems... – Ian Wood Jan 18 at 21:08.
You have multiple identical IDs in your document fragment you are using the class selector, while you have IDs To quote the freenode#css bot: Explore the intricacies of HTML and CSS here: wsc.opera.com/ , htmlhelp.com/ , css-discuss.incutio.com/ , brainjar.com/ , htmldog.com/ , http://css.maxdesign.com.au.
In truth, the css method could easily be chained to the jQuery object directly after we set the link’s title attribute, but they’re separated here for better readability. Within the css method, we specify the fontSize style attribute and use the standard JavaScript ternary conditional to check whether the current value of the freq property divided by 10 is less than 1. If it is, we add 1 to the figure and then concatenate the string em on the end.
This will ensure that none of the tags have a font-size of less than 1em, which is equal to our 70% style rule set on the container element. However if the value of the freq property divided by 10 is not less than 1, we then check (using another ternary, the equivalent of nesting for loops) whether it is greater than 2; if it is, we simply use 2em as the value of the font-size property.
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