JQuery - multiple $(document).ready …?
All will get executed and On first Called first run basis! Div id="target"> $(document). Ready(function(){ jQuery('#target').
Append('target edit 1'); }); $(document). Ready(function(){ jQuery('#target'). Append('target edit 2'); }); $(document).
Ready(function(){ jQuery('#target'). Append('target edit 3'); }) Demo Also one thing I would like to mention in place of this $(document). Ready(function(){}) you can use this shortcut jQuery(function(){ //dom ready codes }).
All will get executed and On first Called first run basis! $(document). Ready(function(){ jQuery('#target').
Append('target edit 1'); }); $(document). Ready(function(){ jQuery('#target'). Append('target edit 2'); }); $(document).
Ready(function(){ jQuery('#target'). Append('target edit 3'); }); Demo Also one thing I would like to mention in place of this $(document). Ready(function(){}); you can use this shortcut jQuery(function(){ //dom ready codes }).
Execution is top-down. First come, first served. If execution sequence is important, combine them.
$(document).ready(); is the same as any other function. It fires once the document is ready - ie loaded. The question is about what happens when multiple $(document).ready()'s are fired not when you fire the same function within multiple $(document).ready()'s //this $(document).
Ready(function(){ jQuery('#target'). Append('target edit 1'); }); $(document). Ready(function(){ jQuery('#target').
Append('target edit 2'); }); $(document). Ready(function(){ jQuery('#target'). Append('target edit 3'); }); //is the same as $(document).
Ready(function(){ jQuery('#target'). Append('target edit 1'); jQuery('#target'). Append('target edit 2'); jQuery('#target').
Append('target edit 3'); }); both will behave exactly the same. The only difference is that although the former will achieve the same results. The latter will run a fraction of a second faster and requires less typing.
:) in conclusion where ever possible only use 1 $(document).ready(); //old answer They will both get called in order. Best practice would be to combine them. But don't worry if its not possible.
The page will not explode.
Edited mine as I thought people might get confused between running the same function multiple times and running different functions in multiple $(document). Ready's. ^^ hope it helps.
– Ed Fryed Mar 12 at 1:13.
Both will get called, first come first served. Take a look here. $(document).
Ready(function(){ $("#page-title"). Html("Document-ready was called! "); }); $(document).
Ready(function(){ $("#page-title"). Html("Document-ready 2 was called! "); }); Output: Document-ready 2 was called!
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