If you want to remove all empty tabs, you can use this code.
If you want to remove all empty tabs, you can use this code: $(function() { var $tabs = $( "#tabs" ); $tabs.tabs(); var offst = 0; $('#tabs > div'). Each(function(index, elem) { if ($(elem).html().trim() === '') { $tabs. Tabs( "remove" , index - offst); offst++; } }); }); Here's an example on jsfiddle Notes: The reason for the offst variable is because, if you remove a tab, the indexes will change.
This caches the tabs element in $tabs so it doesn't have to call the selector multiple times. This uses the proper remove function of jQuery UI tabs.
This worked great for my problem. Many thanks! – areid Mar 30 at 10:11 @aried: You're welcome.
:) – Drackir Apr 1 at 15:14.
Try this if ($('#tabs-3'). Is(':empty')) { var tabId = $(this). Attr('id'); $('ahref$="'+tabId+'"').parent().remove(); } For given tab id this should remove the parent element (and everything within it) of an anchor which has a matching href.
Edit: btw, your third div won't match ':empty' condition unless it really is empty, ie.
I think you're on the right track, but check out $('#tabs'). Tabs('remove',index) as a better way to get rid of the unwanted tab! – Ryley Mar 21 at 21:34.
You can find the code at this link: jsfiddle.net/sJkyE/ Regards.
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